• emergencyfood@sh.itjust.works
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    2 months ago

    Not a mathematician, but I’m pretty sure this isn’t necessarily true. What if L is -1 and f(x) = x^2? Also I think your function has to be continuous.

    • davidagain@lemmy.world
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      2 months ago

      You’re right on all three counts. It’s not always true, f(x0) has to be L, and the function has to be continuous.